In beaumonts lesson we did the find the relative atomic mass of an unkown metal by gas collection.
x (unkown metal) = 0.20 g
1MHCL we used 25cm3
Volume of hydrogen gas we found out was 192 cm3 (in my experiment).
Equation was : x + 2HCl = xCl2 + H2
We were told to find the relative atomic mass of x, which I found was 25 (in my experiment)
On the sheet for the experiment that we were given, one question is "Calculate amounts in moles (using your value Ar for x) to show that the acid was in excess".
any ideas on this one? when i converted moles of HCl (which i found by multiplying moles of x by two) to volume (v=24000n) i found it was way greater than the 25cm3 we used. how do i do it:S?
4 comments:
yea like i said earlier isn't it 1000 not 24000 as HCl isn't a gas?
Where did you get the 24000 from? Solutions are to do with concentration whereas 24000 is about gases and volumes. Use the concentraion = moles/volume formula.
thanks a lot. makes sense now. don't know why i didn't see that.
in the end i used v=n/c which meant i needed 16cm3 of HCl.
cheers(Y)
another question was how would you modify the procedure if metal x was provided in lump form.
only thing i thought was that you would need more HCl so that it fully covered the lump?
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