Question 5
On the answers it says you multiply the moles of IO3(-), which is 2.3 x 10^-3, by the molar mass of iodine. Isn't it I2, and so you would multiply by not 127, but 127 x 2?
Is it because the iodine is involved in a compound and so we use simply the molar mass of I, not I2??
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2 comments:
I haven't got the question that you're referring to in front of me, Lewis, but I seem to recall that it involves working out the number of moles of IO3-, then using the 1:1 ratio of IO3-:I2 (given in the question) to work out the number of moles of I2 that this would be converted into.
Therefore, when working out the mass of iodine formed, you would be using a relative mass of (127 x 2), just as you suggested. This is because each molecule of iodine contains two atoms of I.
Hope this helps!
thanksss.
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