Question 3 "what volume of 0.500M sodium hydroxide is needed to neutralise 22.5cm^3 of a solution of 0.262M sulphuric acid?" of task 1.2f is confusing me.
I've worked out they react in a 2:1 ratio but without the concentration of sodium hydroxide I am unable to find the volume. the answer given is 23.6cm^3 but I have no idea how that answer camt to be.
can someone help please?
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You have been making great use of the blog recently, Stephen - well done!
You have been given the concentration and volume of H2SO4. What can you calculate using this information?
you can calculate the moles of H2SO4 used which i found to be 0.0116. then working out the equation i found that 2NaOH + H2SO4 -> Na2SO4 + H2O so they react in a 2:1 ratio
In the question you were given the concentration of sodium hydroxide - 0.500M.
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